(x)=2x^2+3x+1000

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Solution for (x)=2x^2+3x+1000 equation: 



(x)=2x^2+3x+1000

We move all terms to the left:

(x)-(2x^2+3x+1000)=0

We get rid of parentheses

-2x^2+x-3x-1000=0

We add all the numbers together, and all the variables

-2x^2-2x-1000=0

a = -2; b = -2; c = -1000;
Δ = b2-4ac
Δ = -22-4·(-2)·(-1000)
Δ = -7996
Delta is less than zero, so there is no solution for the equation

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